5d^2-d=0

Solution for 5d^2-d=0 equation:

5d^2-d=0

We add all the numbers together, and all the variables

5d^2-1d=0

a = 5; b = -1; c = 0;
Δ = b2-4ac
Δ = -12-4·5·0
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$d_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$d_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1}=1$
$d_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-1}{2*5}=\frac{0}{10}
=0
$
$d_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+1}{2*5}=\frac{2}{10}
=1/5
$